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boiler thermal efficiency

Introduction: It is the ratio of heat output to heat input of the boiler. Boiler efficiency= Heat output / heat input *100. =steam flow (enthalpy of steam -enthalpy of feed water) / coal flow * gcv. For example if there is a 80mw boiler with 540 dig centigrade of main steam temperature, feed water temperature of 300 dig centigrade , coal flow 56 ton, gcv 4000 kcal/kg then the boiler efficiency will be =307(826.28-242.58)/56*4000=80%.

Calculation of positive balance of boiler thermal efficiency

Thermal efficiency of gas boiler = all the heat released by effective utilization of heat/fuel * 100%
= boiler evaporation * (steam enthalpy-feedwater enthalpy)/fuel consumption * low calorific value of fuel * 100%

Inverse balance calculation of boiler thermal efficiency

Boiler thermal efficiency = 100%-the sum of the percentages of various heat losses.
① Exhaust heat loss. The heat loss will increase by about 1% for every 13℃ rise of exhaust temperature, that is, (exhaust temperature-room temperature) /13.
② For example, when the exhaust temperature is 200℃ and the room temperature is 20℃, the exhaust heat loss is about (200-20)/13=13.8, and the exhaust heat loss is 13.8%.
③ Heat loss from incomplete combustion of gas. The layer combustion is about 1~2%, the chamber combustion is about 0.5~1%, and the boiling furnace is ≤0.5%.
④ Heat loss from incomplete combustion of machinery.
⑤ Heat loss. The larger the boiler, the smaller the heat loss, which is generally 0.8~3%.
⑥ Physical heat loss of ash.

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